A nucleus of atomic mass M emits a gamma ray photon of frequency v. then

Kinetic energy acquired by nucleus

= \frac{h^{2} v^{2}}{2 M c^{2}}

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Loss in the internal energy of the nucleus

h v (1 + \frac{h v}{2 M c^{2}})

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Momentum of nucleus is equal and opposite to

γ

ray photon

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Loss in internal energy of nucleus is hv

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Solution

The correct option is A Kinetic energy acquired by nucleus $= \frac{h^{2} v^{2}}{2 M c^{2}}$
Hence, option $(A)$ is correct answer.

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A nucleus of atomic mass M emits a gamma ray photon of frequency v. then

The correct option is A Kinetic energy acquired by nucleus =h2v22Mc2Hence, option (A) is correct answer.

The correct option is A Kinetic energy acquired by nucleus $= \frac{h^{2} v^{2}}{2 M c^{2}}$
Hence, option $(A)$ is correct answer.