A nucleus of mass M+Δm is at rest and decays into two daughter nuclei of equal mass M2 each. Speed of light is c. The binding energy per nucleon for the parent nucleus is E1 and that for the daughter nuclei is E2. Then :
A
E2>2E1
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B
E1>E2
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C
E2>E1
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D
E1=2E2
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Solution
The correct option is BE1>E2 let x→2y mass →M+Δm2×M2=MΔm mass is lost as energy ⇒ energy is released ⇒ energy of x> energy of y E1>E2 option B