A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c$ .
The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then

$E_{2} = E_{1}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$E_{1} > E_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$E_{2} > E_{1}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$E_{1} = 2 E_{2}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$E_{2} > E_{1}$

The reaction is $X \to 2 Y$
$X \to m a s s i s M + △ m$
$Y \to m a s s i s \frac{M}{2}$

Now, this is energetically feasible only if the daughter nucleus has a higher binding energy than the parent, so $E_{2} > E_{1} .$

Suggest Corrections

Similar questions

A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c$ .
The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then