A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c$ .
The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then
[AIEEE-2010]

E_{2} = 2 E_{1}

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E_{1} > E_{2}

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E_{2} > E_{1}

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E_{1} = 2 E_{2}

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Solution

The correct option is C $E_{2} > E_{1}$
Easy one dude,
The reaction is $X \to 2 Y$
$X \to m a s s i s M + △ m$
$Y \to m a s s i s \frac{M}{2}$

Now, this is energetically feasible only if the daughter nucleus has a higher binding energy than the parent, so $E_{2} > E_{1} .$

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A nucleus of mass $M + △ m$ is at rest and decays into two daughter nuclei of equal mass $\frac{M}{2}$ each. Speed of light is $c$ .
The binding energy per nucleon for the parent nucleus is $E_{1}$ and that for the daughter nuclei is $E_{2}$ . Then