A nucleus of stable phosphorus has 15 protons and 16 neutrons. What will be the atomic number and mass number of new nucleus formed by decay of a $β$ -particle by the phosphorus nucleus?

15, 32

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16, 32

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15, 30

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16, 30

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Solution

The correct option is B 16, 32
$β$ decay converts 1 neutron to the 1 proton. So the atomic number increases by 1.
So, atomic number is number of protons $= 16$ .
Mass number is number of protons+number of neutrons $= 16 + 16 = 32$ .

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A nucleus of stable phosphorus has 15 protons and 16 neutrons. What will be the atomic number and mass number of new nucleus formed by decay of a β-particle by the phosphorus nucleus?

The correct option is B 16, 32β decay converts 1 neutron to the 1 proton. So the atomic number increases by 1.So, atomic number is number of protons =16.Mass number is number of protons+number of neutrons =16+16=32.

A nucleus of stable phosphorus has 15 protons and 16 neutrons. What will be the atomic number and mass number of new nucleus formed by decay of a $β$ -particle by the phosphorus nucleus?

The correct option is B 16, 32
$β$ decay converts 1 neutron to the 1 proton. So the atomic number increases by 1.
So, atomic number is number of protons $= 16$ .
Mass number is number of protons+number of neutrons $= 16 + 16 = 32$ .