Question

A nucleus undergoes a series of decay according to the scheme $A\stackrel{\alpha }{\to }B\stackrel{\beta }{\to }C\stackrel{\alpha }{\to }D\stackrel{\gamma }{\to }E$. Atomic number and mass numbers of E are 69 and 172

• A. Atomic number of $A$ is 72
• B. Mass number of $B$ is 176
• C. Atomic number of $D$ is 69
• D. Atomic number of $C$ is 69

Answer 1

Answer: (A), (B), (C)

The correct options are
A Atomic number of $A$ is 72
B Mass number of $B$ is 176
C Atomic number of $D$ is 69