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Question

A nucleus with atomic number Z and neutron number N undergoes two decay processes. The result is a nucleus with atomic number Z-3 and neutron number N-1. Which decay processes took place?

A
Two β decays
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B
Two β+ decays
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C
An αdecay and a β decay
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D
An αdecay and a β+ decay
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Solution

The correct option is D An αdecay and a β+ decay
α2n+2p
β+pn
neutron no.
decrease of 2 by α
decrease of 1 by β
Atomic No.
decrease of 2 by α
increase of 1 by β
.
Let no. of alpha decay be n1
Let no. of β decay be n2
then
Z2n1n2=Z3
and
N2n1+n2=Z1
Solving
n1=1
n2=1

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