A nucleus X is in the higher energy state where its energy is 450 keV . If it comes to ground state (assuming ground state energy to be zero), what is the wavelength of the photon emitted?

2.76 \times 10^{- 9} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.76 \times 10^{- 10} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.76 \times 10^{- 11} m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.76 \times 10^{- 12} m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $2.76 \times 10^{- 12} m$
The energy of the photon that comes out must equal the difference in the energy levels between which the nucleus transitions.
$E p h o t o n = \frac{h c}{λ} = | Δ E_{n u c l e u s} | = 450 k e V$
$\Rightarrow \frac{h c}{450 k e V} = \frac{1242 e V . n m}{450 \times 10^{3} e V} = 2.76 p m = 2.76 \times 10^{- 12} m .$

Suggest Corrections

Similar questions

Q. A nucleus

X

is in the higher energy state where its energy is

450 k e V

. If it comes to ground state (assuming ground state energy to be zero), what is the wavelength of the photon emitted?

Suppose a $_{88}^{226} R a$ nucleus at rest and in ground state undergoes $α$ -decay to a $_{86}^{222} R n$ nucleus in its excited state. The kinetic energy of the emitted $α$ particle is found to be $4.44 M e V$ . $_{86}^{222} R n$ nucleus then goes to its ground state by $γ$ -decay. The energy of the emitted $γ$ photon is $k e V$ .

[Given : atomic mass of $_{88}^{226} R a = 226.005 u$ , atomic mass of $_{86}^{222} R n = 222.000 u$ , atomic mass of $α$ particle = $4.000 u, 1 u = 931 M e V / c^{2}, c$ is speed of light]

Q. The ground state energy of hydrogen atom is - 13.6e V.
(A) What is the potential energy of an electron in the 3rd excited state?
(B) If the electron jump to the ground state from the 3rd excited state,calculate the wavelength of the photon emitted.

Q. In a hydrogen atom, the energy of an electron in an orbit is

- 3.4

eV. When it is excited to the next higher energy level and comes back to ground state, calculate the wavelength of emitted radiation.

Q. Below is shown the energy-level diagram of hydrogen like imaginary element X. (hc = 1242 eV-nm)

Join BYJU'S Learning Program

A nucleus X is in the higher energy state where its energy is 450 keV . If it comes to ground state (assuming ground state energy to be zero), what is the wavelength of the photon emitted?

The correct option is D 2.76×10−12mThe energy of the photon that comes out must equal the difference in the energy levels between which the nucleus transitions. Ephoton=hcλ=|ΔEnucleus|=450 keV ⇒hc450 keV=1242 eV.nm450×103 eV=2.76pm=2.76×10−12m.