A nucleus ZAX emits an - -particle- the resultant nucleus emits a - - particle- the respective atomic and mass numbers of the final nucleus will be

The correct option is A Z 3,A 4 _Z^A Xα particle / _Z 2^A 4 X #160; β^+/_ #160; #160; Z 2^A 4 X So, (Z 3,A 4) ...

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Standard XII

Chemistry

Group Displacement Law

A nucleus Z...

Question

A nucleus $_{Z}^{A} X$ emits an $α - p a r t i c l e$ . the resultant nucleus emits a $β^{+}$ particle. the respective atomic and mass numbers of the final nucleus will be

Z-3,A-4

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Z-1,A-4

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Z-2,A-4

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Z,A-2

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Solution

The correct option is A Z-3,A-4
$_{Z}^{A} X \frac{α -particle}{}_{Z - 2}^{A - 4} X {\frac{β^{+}}{}} {Z - 2}^{A - 4} X$

$So, (Z-3,A-4)$

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A nucleus AZX emits an α−particle. the resultant nucleus emits a β+ particle. the respective atomic and mass numbers of the final nucleus will be

The correct option is A Z-3,A-4AZXα -particle A−4Z−2Xβ+ Z−2A−4XSo, (Z-3,A-4)

A nucleus $_{Z}^{A} X$ emits an $α - p a r t i c l e$ . the resultant nucleus emits a $β^{+}$ particle. the respective atomic and mass numbers of the final nucleus will be

The correct option is A Z-3,A-4
$_{Z}^{A} X \frac{α -particle}{}_{Z - 2}^{A - 4} X {\frac{β^{+}}{}} {Z - 2}^{A - 4} X$

$So, (Z-3,A-4)$