A nuclide X of mass number 233 emits six - particles and same number of - - particles- The mass number of the daughter nuclide is

The correct option is A 209 ^233X → 6 #160; #160; ^4_2He + 6 β + #160; ^AY 233 = 6× 4 + 0 + A ⇒ A = 209 ...

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Standard X

Physics

Alpha Decay

A nuclide X o...

Question

A nuclide (X) of mass number 233 emits six $α$ - particles and same number of $β$ - particles. The mass number of the daughter nuclide is

208

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209

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207

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206

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Solution

The correct option is A 209
$^{233} X \to 6_{2}^{4} H e + 6 β +^{A} Y$
$233 = 6 \times 4 + 0 + A$
$\Rightarrow A = 209$

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A nuclide (X) of mass number 233 emits six α- particles and same number of β - particles. The mass number of the daughter nuclide is

The correct option is A 209233X→642He+6β+AY233=6×4+0+A⇒A=209

A nuclide (X) of mass number 233 emits six $α$ - particles and same number of $β$ - particles. The mass number of the daughter nuclide is

The correct option is A 209
$^{233} X \to 6_{2}^{4} H e + 6 β +^{A} Y$
$233 = 6 \times 4 + 0 + A$
$\Rightarrow A = 209$