Question

A number 34A is exactly divisible by 2 and leaves a remainder 1, when divided by 7 find A.

Answer 1

The number is exactly divided by $2$ so The Number $A$ must be one of $0,2,4,6,8$

Let it be $0$

So the number is $340$

So when it is divided by $7$ it leaves the remainder $4\ne 1$

Let it be $2$

So the number is $342$

So when it is divided by $7$ it leaves the remainder $6\ne 1$

Let it be $4$

So the number is $344$

So when it is divided by $7$ it leaves the remainder $1$

So the number is $4$