Question

A number 74A is exactly divisible by 2 and leaves a remainder 1, when divided by 5. Find A.

• A. 2
• B. 4
• C. 6
• D. 8

Answer 1

The correct option is C 6

Here, 74A is exactly divisible by 2.
If a number is even then it is divisible by 2.
$\therefore$ Possible values of A = 0, 2, 4, 6, 8 ... (i)

Now, if a number has 0 or 5 in its ones place then the number is divisible by 5.
74A leaves a remainder 1 when divided by 5.
$\therefore$ Possible values of A = 1,6 .... (ii)
From (i) and (ii) we get
A = 6