Let no. at unit's place be x
Let no. at tens place be 10y
Let no. at hundred's place be 100z
Also let The NO. = a
A.T.Q, 10y=0 ...y=0........(i)
Also 100z+10y+x =a..............(ii)
NOW,A.T.Q
100x+10y+z = a+198 .........(iii)
SUBTRACTING (iii)FROM (ii)
100z + 10y + x =+ a
+ z + 10y + 100x = +a+198
- - - - -
99z-99x=-198
z-x=-2......(iv)
ALSO,A.T.Q
50z+y+10x = a-228……(v)
SUBTRACTING(v) from (ii)
100z+10(0)+x-50z-(0)-10x
=a-a+228(... y=0)
50z-9x=228........(vi)
Putting in(vi)
50z-9(z+2)=228
=>z=6
PUTTING in (vii)
x=6+2=8
THEREFORE NO.=100z+10y+x=608