A number consists of two digits such that the digit in the unit’s place is more by 2 than the digit in the ten’s place. Three times the number added to $\frac{6}{7}$ times the number obtained by reversing the digits equals 108. Then the number is:

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Solution

The correct option is A 24

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Similar questions

If the digit in the unit’s place of a two – digit number is halved and the digit in the ten’s place is doubled, the number thus obtained is equal to the number obtained by interchanging the digits. Which of the following is definitely true?

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A two-digit number is such that the ten's digit exceeds twice the unit's digit by 2 and the number obtained by inter-changing the digits is 5 more than three times the sum of the digits. Find the two digit number.

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A number consists of two digits such that the digit in the unit’s place is more by 2 than the digit in the ten’s place. Three times the number added to 67 times the number obtained by reversing the digits equals 108. Then the number is:

The correct option is A 24

A number consists of two digits such that the digit in the unit’s place is more by 2 than the digit in the ten’s place. Three times the number added to $\frac{6}{7}$ times the number obtained by reversing the digits equals 108. Then the number is: