A number consists of two digits whose sum is 9. If 27 is added to the number, its digits are interchanged. Are the given steps to find the number true?
Step 1: Let the unit's digit be x
Step 2: Then, ten's digit =(9−x)
∴ number =10×(9−x)+x⇒90−10x+x=(90−9x)
Step 3: Adding 27 to the number 90−9x we get 117−9x
Step 4: Number with digits interchanged is 10x+(9−x)=9x+9
Step 5: 117−9x=9x+9
Step 6: Therefore unit's digit=6 and ten's digit =3
Step 7: Hence the number =36.