A number is $27$ more than the number obtained by reversing its digit. Find the number.

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Solution

Let $X$ be tens digit and $Y$ be ones digit so the number is $10 X + Y$
After Adding $27$ digits reversed $⟹ 10 X + Y + 27 = 10 Y + X$
$9 X + 27 = 9 Y ⟹ X + 3 = Y$
$⟹ n u m b e r = 14, 25, 36, 47, 58, 69$

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A number is 27 more than the number obtained by reversing its digit. Find the number.

Let X be tens digit and Y be ones digit so the number is 10X+YAfter Adding 27 digits reversed ⟹10X+Y+27=10Y+X9X+27=9Y⟹X+3=Y⟹number=14,25,36,47,58,69

A number is $27$ more than the number obtained by reversing its digit. Find the number.

Let $X$ be tens digit and $Y$ be ones digit so the number is $10 X + Y$
After Adding $27$ digits reversed $⟹ 10 X + Y + 27 = 10 Y + X$
$9 X + 27 = 9 Y ⟹ X + 3 = Y$
$⟹ n u m b e r = 14, 25, 36, 47, 58, 69$