The correct option is A 132 and 68
Let the numbers be x and y
As per the given statement form a first equation as,
x=2y−4 ----------- (1)
Second equation as,
x+y=200 ------------ (2)
By subtracting equation 1 and 2, we get
x−2y=−4
x+y=200
___________
−3y=−204
y=68
Put the value of y in equation (2)
x+68=200
x=200−68
x=132
Therefore, the numbers are 132 and 68.