Question

A number is as much greater than 21 as it is less than 71. Find the number.

Answer 1

$\begin{array}{l}\text{Let the number be}x.\\ \text{Then, we have:}\\ (x-21)=(71-x)\\ \Rightarrow x+x=71+21\\ \Rightarrow 2x=92\\ \Rightarrow x=\frac{\sout{9}{\sout{2}}^{46}}{{\sout{2}}_1}\\ \Rightarrow x=46\\ \therefore \text{The required number is 46.}\end{array}$