A number is chosen at random among the first $120$ natural numbers. The probability of the number chosen to be a multiple of $5$ or $15$ is:

\frac{1}{5}

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\frac{1}{6}

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\frac{1}{7}

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\frac{1}{9}

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Solution

The correct option is A $\frac{1}{5}$
A number which is a multiple of $15$ will surely be a multiple of $5$ . There are $24$ multiples of $5$ from 1 to $120$
Hence, favorable outcomes $= 24$
Total outcomes $= 120$
Probability = $\frac{24}{120}$ = $\frac{1}{5}$

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A number is chosen at random among the first 120 natural numbers. The probability of the number chosen to be a multiple of 5 or 15 is:

The correct option is A 15A number which is a multiple of 15 will surely be a multiple of 5. There are 24 multiples of 5 from 1 to 120Hence, favorable outcomes =24Total outcomes =120Probability = 24120 = 15

A number is chosen at random among the first $120$ natural numbers. The probability of the number chosen to be a multiple of $5$ or $15$ is:

The correct option is A $\frac{1}{5}$
A number which is a multiple of $15$ will surely be a multiple of $5$ . There are $24$ multiples of $5$ from 1 to $120$
Hence, favorable outcomes $= 24$
Total outcomes $= 120$
Probability = $\frac{24}{120}$ = $\frac{1}{5}$