Question

A number is divisible by both $2\&3.$ Find a smallest positive number, other than $1,2\text{or}3,$ that divides the original number completely.

Answer 1

The number which is divisible by both $2$ and $3$ is also divisible by $6,$ since $2$ and $3$ are factors of $6.$
$\Rightarrow 6=2\times 3$

Also, $6$ is the smallest positive number other than $1,2$ or $3,$ which divides the number(divisible by 2 and 3) without any remainder.