Question

A number is first increased by 20% and then reduced by 20%. What would be the percentage change in the number?

• A. 0
• B. 2
• C. 4
• D. 6

Answer 1

Answer: (C)

4

Let the number be $100$

$20\%$ increase in $100=100+\frac{20}{100}\times 100=120$

$20\%$ decrease in $120=120-120\times \frac{20}{100}=96$

$\therefore$ change in number $=\frac{(96-100)}{100}\times 100=-4\%$

Hence, there is a decrease in number of $4\%$