Question

A number is increased by $20\%$ and then decreased by $20\%$ find the net increase or decrease percent.

Answer 1

Let the number be $x$

Given the number is increased by $20\%$

So the new number will be $\frac{100+20}{100}x=1.2x$

Now the number is decreased by $20\%$

So the new number is $\frac{100-20}{100}\left(1.2x\right)=0.96x=\frac{100-4}{100}x$

Net decrease in percent is $4\%$