A number is randomly selected from the list: 1,3,3, 6,6,6,8,8,8,8,10,10,10,10. X = {3 is selected} Y = {6 is selected} X and Y are events.
A
equally likely
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B
not equally likely
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C
exhaustive
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Solution
The correct option is B not equally likely Let's look at the list of numbers again. We have two 3s there and three 6s. So if I pick a number randomly there are more chances that I will put my hand at a 6 when compared to 3. I may end up selecting 3. But chances of 6 being selected is more. So X and Y are not equally likely.