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Intersection of Sets

A number is s...

Question

A number is selected from the set {1, 2, 3, 4, 5, 6, 7, 8}. What is the probability that it will be the root of the equation $x^{2} - 6 x + 8 = 0$ ?

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Solution

There are 8 numbers.
The roots of the equaton $x^{2} - 6 x + 8 = 0$ are 2 and 4.
The number of favourable outcomes is 2.
Therefore,
Required probability = $\frac{2}{8} = \frac{1}{4}$ .

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