A number lock has 4 dials, each dial has the digits 0, 1, 2, .....,9 What is the maximum unsuccessful attempts to open the lock ?

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Solution

$4$ dials, each has $10$ digits $(0 - 9)$
$¯ 10 ¯ 10 ¯ 10 ¯ 10$
Total combinations $= 10 \times 10 \times 10 \times 10$
$= 10000$
Since there will be one successful combination, therefore there are $9999$ unsuccessful attempts to open the lock.

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A number lock has 4 dials, each dial has the digits 0, 1, 2, .....,9 What is the maximum unsuccessful attempts to open the lock ?

4 dials, each has 10 digits (0−9)¯10¯10¯10¯10Total combinations=10×10×10×10=10000Since there will be one successful combination, therefore there are 9999 unsuccessful attempts to open the lock.

$4$ dials, each has $10$ digits $(0 - 9)$
$¯ 10 ¯ 10 ¯ 10 ¯ 10$
Total combinations $= 10 \times 10 \times 10 \times 10$
$= 10000$
Since there will be one successful combination, therefore there are $9999$ unsuccessful attempts to open the lock.