A number lock on a suitcase has $3$ wheels each labeled with $10$ digits from $0$ to $9$ . If the opening of the lock is a particular sequence of three digits with no repeats, how many such sequences will be possible?

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Solution

On the first wheel, there can be $10$ digits.

On the second wheel, there will be one of the $9$ digits and on the third wheel, there will be $8$ digits.

Therefore, the number of numbers is $10 \times 9 \times 8 = 720$ .

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A number lock on a suitcase has 3 wheels each labeled with 10 digits from 0 to 9. If the opening of the lock is a particular sequence of three digits with no repeats, how many such sequences will be possible?

On the first wheel, there can be 10 digits. On the second wheel, there will be one of the 9 digits and on the third wheel, there will be 8 digits. Therefore, the number of numbers is 10×9×8=720.

A number lock on a suitcase has $3$ wheels each labeled with $10$ digits from $0$ to $9$ . If the opening of the lock is a particular sequence of three digits with no repeats, how many such sequences will be possible?

On the first wheel, there can be $10$ digits.

On the second wheel, there will be one of the $9$ digits and on the third wheel, there will be $8$ digits.

Therefore, the number of numbers is $10 \times 9 \times 8 = 720$ .