A number of discs, each of momentum 'M' kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

\frac{M n}{60}

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60 M n

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\frac{M}{60 n}

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\frac{n}{60 M}

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Solution

The correct option is A $\frac{M n}{60}$
no of discs striking per second is = $\frac{n}{60}$
so force on wall = $\frac{n * M}{60}$
so the answer is A.

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A number of discs, each of momentum 'M' kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

The correct option is A Mn60no of discs striking per second is = n60so force on wall = n∗M60so the answer is A.

The correct option is A $\frac{M n}{60}$
no of discs striking per second is = $\frac{n}{60}$
so force on wall = $\frac{n * M}{60}$
so the answer is A.