A number "p" exists such that it is the square of a number "q". If "p" $>$ 400, "q" can be any number greater than

True

No worries! We‘ve got your back. Try BYJU‘S free classes today!

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
C
25

D
29

The square root of 400 is $\sqrt{400}$ = 20.

So if "p" $>$ 400, its square root can be any number greater than 20.

Suggest Corrections

Similar questions

A number "p" exists such that it is the square of a number "q". If "p" $>$ 400, "q" can be

A number 'p' exists such that it is the square of a number 'q'. If 'p' $>$ 400, 'q' can be:

Find the negation of the statement - 'There exists a rational number x such that its square is 2 '.

l > 0

C

l,

T

l .

Join BYJU'S Learning Program