Question

A number plus two-third of itself, plus one-half of itself plus one-seventh of itself equals $97$. Find the number.

Answer 1

Let number be $x$

$\therefore x+\frac{2x}{3}+\frac{x}{2}+\frac{x}{7}=97$

$\therefore \frac{42x+28x}{42}+21x+6x=97$

$\therefore \frac{97x}{42}=97$

$\therefore x=42$