Question

A number was divided successively in order by 4, 5 and 6 The remainders were respectively 2, 3 and 4 Then find out the number

Answer 1

4 | x |
5 | y | 2
6 | z | 3
| 1 | 4
$\therefore$ z = (6 x 1 + 4) = 10
$\therefore$ y = (5 x z x 3) = (5 x 10 + 3) = 53
$\therefore$ x = (4 x y + 2) = (4 x 53 + 2) = 214
Hence the required number is 214