Question

A number was divided successively in order by $4,5$ and $6$. The remainders were respectively $2,3$ and $4$. The number is:

• A. $214$
• B. $476$
• C. $954$
• D. $1908$

Answer 1

The correct option is A $214$

Going in reverse order:

Let the number be z,y,x before division by 6,5,4 respectively.

We know,

Dividend = Divisor$\times$ Quotient + Remainder

According to the given conditions:

$z=6\times 1+4$

$\therefore z=10$

Also, $y=5\times z+3$

$y=53$

Also, $x=4\times y+2$

$x=214$

Hence, the required number is 214.