Question

A number when divided by $114$ leaves the remainder $21.$ If the same number is divided by $19$ the remainder will be

• A. $1$
• B. $2$
• C. $7$
• D. $21$

Answer 1

The correct option is B $2$

We know that,

$Dividend=(Divisor\times Quotient)+Remainder$

Let the number be ${}^{\prime }{n}^{\prime }=114q+21.$
Then $n=(6\times 19)q+21$
$=19\times \left(6q\right)+21$
$=19\times (6q+1)+2$
Hence, the remainder is $2.$