Question

A number, when divided by 6, leaves a remainder 3. When the square of that number is divided by 6, the remainder is 3.

• A. 3
• B. 1

Answer 1

The correct option is A

3

Let the number be x.
$x=6q+3$
Then,
$x^2=(6q+3{)}^2$
=$36q^2+36q+9$
=$6(6q^2+6q+1)+3$
Thus, when $x^2$ is divided by 6, then remainder is 3.