Question

A number when divided by 8 gives 5 as its remainder. What would the remainder be if twice the same number is divided by 8?

• A. 2
• B. 1
• C. 3
• D. 4

Answer 1

The correct option is A 2

Let the unknown number be N.

$Dividend=NDivisor=8Quotient=QRemainder=5$

As we know,

$Dividend=(Divisor\times Quotient)+Remainder$

$⟹N=8Q+5$

Now,

$2N=N+N=(8Q+5)+(8Q+5)=16Q+10=16Q+(8+2)=(16Q+8)+2=8(2Q+1)+2$

Taking 2Q + 1 as the natural number M, we get:

$2N=8M+2$

Taking the dividend as 2N and the divisor as 8, we get:

$Dividend=(Divisor\times M)+2⟹Quotient=M;Remainder=2$