Question

A number when divided successively by 6, 7 and 8, it leaves the respective remainders of 3, 5 and 4. What will be the last remainder when such a least possible number is divided successively by 8, 7 and 6? ___

Answer 1

First we find the actual least possible no. then we move further

((((4 $\times$ 7) + 5) $\times$ 6) + 3) = (((28 + 5) $\times$ 6) + 3)
= 33 $\times$ 6 + 3 = 198 + 3 = 201
Now we divide 201 successively by 8, 7 and 6.

So 3 is the last remainder.