Question

A number when multiplied by $4$ exceeds itself by $36.$ Find the number.

Answer 1

Let ${}^{\prime }{x}^{\prime }$ be the number, when multiplied by $4$ exceeds itself by $36.$
Now, according to question,we have
$4x=x+36$
$\Rightarrow 4x-x=36$
$\Rightarrow 3x=36$
$\Rightarrow x=\frac{36}{3}$
$\Rightarrow x=12$
Hence, $12$ is the number when multiplied by $4$ exceeds itself by $36.$