1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard VII
Mathematics
Integers
A number whic...
Question
A number which divides 41 and 68 leaves 5 as a remainder . What is the number
Open in App
Solution
41
−
5
=
36
=
2
×
2
×
3
×
3
68
−
5
=
63
=
3
×
3
×
7
H.C.F
(
36
,
63
)
=
3
×
3
=
9
So, answer
=
9
Suggest Corrections
0
Similar questions
Q.
A number when divided by 5 leaves 3 as remainder. if the square of the same number is divided by 5, the remainder obtained is
Q.
A number when divided by 143 leaves 31 as remainder. What will be the remainder when the same number is divided by 13?
(a) 0
(b) 1
(c) 3
(d) 5
Q.
On dividing a number by
68
, we get
269
as quotient and
0
as remainder. On dividing the same number by
67
, what will the remainder?
Q.
A number when divided by
136
, leaves
36
as remainder. If the same number is divided by
17
, what will be the remainder?
Q.
Find the least number which when divided by
15
, leaves a remainder of
5
, when divided by
25
, leaves a remainder of
15
and when divided by
35
leaves a remainder of
25
.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Integers
MATHEMATICS
Watch in App
Explore more
Integers
Standard VII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Solve
Textbooks
Question Papers
Install app