Question

A number x is chosen at random from the set {$1,2,3,4,...,100$}. Define the event : $A=$ the chosen number x satisfies $\frac{(x-10)(x-50)}{(x-30)}⩾0$ . Then $P\left(A\right)$ is :

• A. $0.71$
• B. $0.70$
• C. $0.51$
• D. $0.20$

Answer 1

The correct option is A $0.71$

$\frac{(x-10)(x-50)}{(x-30)}\ge 0$
Events $\Rightarrow$ Number from 10 to 29 + Numbers from 50 to 100
$\Rightarrow 20+51$
$=71$ .
Probability $=\frac{71}{100}=0.71$