A number - x - was found to be represented in the simplest p-q form- The decimal expansion of this number was found to be 6-3333333333 - - Find the value of p-q

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Standard VI

Mathematics

Prime Factors

A number ' x ...

Question

A number 'x' was found to be represented in the simplest $\frac{p}{q}$ form. The decimal expansion of this number was found to be 6.3333333333..... Find the value of p - q.

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Solution

The correct option is C
13

We have $x = 6.3333333......$
Therefore, $10 x = 63.33333333....$
Subtracting both the equations, we get, $10 x - x = 63.33333333.... - 6.3333333...... = 57$
i.e. $x = \frac{57}{9} = \frac{19}{3}$
So, $p - q = 16$

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A number 'x' was found to be represented in the simplest pq form. The decimal expansion of this number was found to be 6.3333333333..... Find the value of p - q.

The correct option is C 13 We have x=6.3333333...... Therefore, 10x=63.33333333.... Subtracting both the equations, we get, 10x−x=63.33333333....−6.3333333......=57 i.e. x=579=193 So, p−q=16

A number 'x' was found to be represented in the simplest $\frac{p}{q}$ form. The decimal expansion of this number was found to be 6.3333333333..... Find the value of p - q.

The correct option is C
13

We have $x = 6.3333333......$
Therefore, $10 x = 63.33333333....$
Subtracting both the equations, we get, $10 x - x = 63.33333333.... - 6.3333333...... = 57$
i.e. $x = \frac{57}{9} = \frac{19}{3}$
So, $p - q = 16$