Question

A nut is opened by a wrench having 20 cm arm length. If the least force required to open the nut is 3.0 N, calculate the moment of the force.

Answer 1

Step 1 Given data:

Force; $F=3N$

Perpendicular distance;$d=20cm=0.2m$

Step 2 Formula used:
Moment of force = Force× perpendicular distance of force from the point of rotation
$M=F\times d$

Step 3 Finding moment of force:
$$\begin{gathered} M=3N\times 0.2m \\ M=0.6Nm \end{gathered}$$
Hence, the moment of a force is $0.6Nm$about an axis of rotation.