A nut is opened by a wrench of length 10cm. If the least force required is 5.0N, find the moment of force needed to turn the nut.
A
50Nm
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B
0.5Ncm
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C
5Nm
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D
0.5Nm
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Solution
The correct option is D0.5Nm Given that we are applying a force of 5 N and a nut is opened by a wrench of length 10cm ( is also equal to 0.1 m). Moment of force is given by formula r×F. Hence 0.1×5=0.5N−m. Hence moment of force is 0.5Nm.