A nut just opens by applying a force of 150 N using a wrench of length 30 cm. If we wants to open it by a force of 50 N then the length of wrench should be:

45 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

90 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 90 cm
Given:
Force, $F = 150 N$
Distance, $d = 30 c m = 0.3 m$

Moment of force required to open the nut is:
$τ = F d$
$τ = 150 N \times 0.3 m = 45 N m$

New force applied, $F_{2} = 50 N$
Let the length of the wrench be $d_{2}$
Torque applied:
$τ = F_{2} d_{2}$
$45 = 50 d$
$d = \frac{45}{50} m$
$d = 0.9 m = 90 c m$

Suggest Corrections

Similar questions

Q. A nut just opens by applying a force of 150 N using a wrench of length 30 cm. If we wants to open it by a force of 50 N then the length of wrench should be:

Q. Vicky opens a nut using a

45 cm

long wrench by applying a force of

220 N

A man can open a nut by applying a force of 150 N by using a lever handle of length 0. 4 m. What should be the length of the handle if he is able to open it by applying a force of 60 N?

Q. A nut is opened by a wrench of length

10 c m

. If the least force required is

5.0 N

, find the moment of force needed to turn the nut.

Q. A mechanic can open a nut by applying a force of 'F' N, while using a lever handle of 'h' cm length. What should be the length of the handle required if he wants to open it, by applying a force of only

(2 F / 3) N

Join BYJU'S Learning Program

A nut just opens by applying a force of 150 N using a wrench of length 30 cm. If we wants to open it by a force of 50 N then the length of wrench should be:

The correct option is C 90 cmGiven: Force, F=150 N Distance, d=30 cm=0.3 m Moment of force required to open the nut is: τ=Fd τ=150 N×0.3 m=45 Nm New force applied, F2=50 N Let the length of the wrench be d2 Torque applied: τ=F2d2 45=50d d=4550 m d=0.9 m=90 cm