Question

A one litre flask contains some mercury. It is found that volume of air inside flask is independent of temperature. If coefficient of volume expansion of flask is $27\times {10}^{-6}{K}^{-1}$ and that of mercury is $1.8\times {10}^{-4}{K}^{-1}$ then volume of mercury in flask is found to be $(100+m)c{m}^3$, then $m$ is

Answer 1

$\Delta V_{glass}=\Delta V_{Hg}\Rightarrow V_g{\gamma }_g\Delta \theta =V_{Hg}{\gamma }_{Hg}\Delta \theta$

$V_{Hg}=\frac{V_g{\gamma }_g}{{\gamma }_{Hg}}=\frac{{10}^3\times 27\times {10}^{-6}}{1.8\times {10}^{-4}}c{m}^3=150c{m}^3$