Question

A one litre glass bulb is evacuated and weighed . The weight is 700 grams. It is then filled with an ideal gas at 1 atm pressure at 312.5 K. The weight of the filled bulb is 702.4 gms The molar weight of the gas is:
(R - 8 ${10}^{-2}$ L atm $K^{-1}mo{l}^{-1}$)

• A. 56
• B. 58
• C. 60
• D. 62

Answer 1

The correct option is C 60

Mass of gas = (702.4 – 700)gms = 2.4 gms
$Pv=\frac{\omega }{m}RT$
$m=\frac{2.4\times 0.08\times 312.5}{1\times 1}=60gmo{l}^{-1}$
Ans: 60