AkA⟶TA product, BkB⟶TB product A and B are two radioactive elements with half-life periods TA and TB (in years) and kA(yr−1) and kB(atom−1year−1).If half-life periods are equal, disintegration rate at the start of disintegration would be:
A
0.693
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B
kATA
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C
both (a) and (b)
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D
None of these
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Solution
The correct option is Dboth (a) and (b) TA=0.693kA by first order rate law (based on unit of kA) TB=1kBa by second order rate law (based on unit of kB) TA=TB (given) ∴0.693kA=1kBa (a = initial activity) ∴kAkB=0.693a (Rate)A=kA(a) (Rate)B=kB(a)2 ∴(Rate)A(Rate)B=kAkBa=0.693=kATA