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Question

AkATA product, BkBTB product
A and B are two radioactive elements with half-life periods TA and TB (in years) and kA(yr1) and kB(atom1year1).If half-life periods are equal, disintegration rate at the start of disintegration would be:

A
0.693
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B
kATA
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C
both (a) and (b)
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D
None of these
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Solution

The correct option is D both (a) and (b)
TA=0.693kA by first order rate law (based on unit of kA)
TB=1kBa by second order rate law (based on unit of kB)
TA=TB (given)
0.693kA=1kBa (a = initial activity)
kAkB=0.693a
(Rate)A=kA(a)
(Rate)B=kB(a)2
(Rate)A(Rate)B=kAkBa=0.693=kATA

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