$A s o d a l i m e ⟶ C_{6} H_{6} C l_{2}, h v ⟶ B$

In this reaction A and B are respectively :

Phenol

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Chlorobenzene

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Sodium benzoate, BHC

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C_{2} H_{2}

& BHC

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Solution

The correct option is A Sodium benzoate, BHC

Benzene can be produced by reduction of acid salt with sodalime.

Then further chlorination of benzene is done in presence of sun light to give benzene hexachloride.

Option C is correct.

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Similar questions

Which of the following cannot be used as a food preservative ?

(a) sodium metabisulphite (b) sodium hydroxide (c) sodium benzoate (d) citric acid

P h C H (C H_{3})_{2} O_{2} - - \to H v A

A a q . H_{2} S O_{4} - ----- \to warm B + C

B C l_{3} + L i A l H_{4} \to A + L i C l + A l C l_{3}

A + H_{2} O \to B + H_{2}

B \to C

N a O H

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