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Question

A p-n photodiode is fabricated from a semiconductor with band gapof 2.8 eV. Can it detect a wavelength of 6000 nm?

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Solution

It is given that a p-n photodiode is fabricated from a semiconductor with band gap of

E g =28eV and wavelength λ=6000nm.

The formula of energy is,

E= hc λ

Substitute the values in above expression.

E= 6626× 10 34 ×3× 10 8 6000× 10 9 =3313× 10 20 J = 3313× 10 20 16× 10 19 E=0207eV

Hence, the energy of the signal of wavelength 6000nm is 0207eV and it is less than the given energy band gap that is 28eV. So, the photodiode cannot detect the signal.


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