Question

A $p$-type semiconductor has acceptor levels $57meV$ above the valance band. The maximum wavelength of light required to create a hole is (Planck's constant $h=6.6\times {10}^{-34}J-s$)

• A. $57\mathring{A}$
• B. $57\times {10}^{-3}\mathring{A}$
• C. $217100\mathring{A}$
• D. $11.61\times {10}^{-33}\mathring{A}$

Answer 1

The correct option is C $217100\mathring{A}$

We know that.

$E=\frac{hc}{\lambda }\Rightarrow \lambda =\frac{hc}{E}=\frac{6.6\times {10}^{-34}\times 3\times {10}^8}{57\times {10}^{-3}\times 1.6\times {10}^{-19}}=217100\stackrel{o}{A}$