A pack of card contain 4 king, 4 queen, 4 aces and 4 knave. A person cut two cards at random, the probability that at least one of them will be an aces is
A
920
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B
19
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C
1120
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D
None of these
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Solution
The correct option is A920 Let E be the event of drawing at least one aces from the pack. Also let A be the event of getting aces and ¯¯¯¯A of getting a card other than aces. then P(E)=(42)+(41)(121)(162)=54120=920