A pack of coffee powder contains a mixture of x g of coffee and y g choco. The amount of coffee powder is greater than that of choco and each pack is at least $10$ g. Which of the following inequalities describe the conditions given?

x < y

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x + y \geq 10

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x + y \leq 10

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x > y

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Solution

The correct options are
B $x + y \geq 10$
C $x > y$
Given A pack of coffee powder contains a mixture of x g of coffee and y g of choco.
The amount of coffee powder is greater than that of choco and each pack is at least 10 g .
The mixture contain x g of coffee powder and y g of choco powder
Then Total weight of mixture $= x + y$
But given total amount of mixture is at least 10 g
$∴ x + y \geq 10$
The weight of coffee powder greater then choco poder
$∴ x > y$

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Similar questions

Solve the following.

Cost of 100g of coffee powder is Rs. 24 and 1kg of tea powder costs Rs.80. Find the ratio of the cost of coffee powder to the tea?

($ x)

($ y)

X

Y

X (s) ⇌ A (g) + 2 B (g); K_{P_{1}} = {9 \times 10}^{- 3} {a t m}^{3}

Y (s) ⇌ 2 B (g) + C (g); K_{P_{2}} = {4.5 \times 10}^{- 3} {a t m}^{3}

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X

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X (S) ⇌ A (g) + 2 B (g); K_{P 1} = 9 \times 10^{- 3} a t m^{3}

Y (s) ⇌ 2 B (g) + C (g); K_{P 2} = 4.5 \times 10^{- 3} a t m^{3}

X

Y

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